Improve UDP address selection.
authorGuus Sliepen <guus@tinc-vpn.org>
Mon, 19 Nov 2012 12:50:17 +0000 (13:50 +0100)
committerGuus Sliepen <guus@tinc-vpn.org>
Mon, 19 Nov 2012 12:50:17 +0000 (13:50 +0100)
We don't need to search the whole edge tree, we can use the node's own edge
tree since each edge has a pointer to its reverse. Also, we do need to make
sure we try the reflexive address often.

src/net_packet.c

index dbf361f..902b081 100644 (file)
@@ -447,24 +447,28 @@ static void choose_udp_address(const node_t *n, const sockaddr_t **sa, int *sock
        if(n->status.udp_confirmed)
                return;
 
-       /* Otherwise, go through the list of known addresses of
-          this node. The first address we try is always the
-          one in n->address; that could be set to the node's
-          reflexive UDP address discovered during key
-          exchange. The other known addresses are those found
-          in edges to this node. */
+       /* Send every third packet to n->address; that could be set
+          to the node's reflexive UDP address discovered during key
+          exchange. */
 
+       static int x = 0;
+       if(++x >= 3) {
+               x = 0;
+               return;
+       }
+
+       /* Otherwise, address are found in edges to this node.
+          So we pick a random edge and a random socket. */
 
        int i = 0;
        int j = rand() % n->edge_tree->count;
        edge_t *candidate = NULL;
 
-       for splay_each(edge_t, e, edge_weight_tree) {
-               if(e->to != n)
-                       continue;
-               i++;
-               if(!candidate || i == j)
-                       candidate = e;
+       for splay_each(edge_t, e, n->edge_tree) {
+               if(i++ == j) {
+                       candidate = e->reverse;
+                       break;
+               }
        }
 
        if(candidate) {